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If the nucleus .(13)^(27)Al has a nuclea...

If the nucleus `._(13)^(27)Al` has a nuclear radius of about `3.6` fm, then `._(52)^(125)Te` would have its radius approximately as

A

`6` fermi

B

`8` fermi

C

`4` fermi

D

`5` fermi

Text Solution

Verified by Experts

The correct Answer is:
A

Radius of a nuclei `prop ("Mass Number")^(1//3)`
`(R_(Te))/(R_(Al)) = ((125)/(27))^(1//3) = (5)/(3) rArr R_(Te) = R_(Al) xx (5)/(3) = 6`
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ALLEN-SIMPLE HARMONIC MOTION-Exercise-04 [B]
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