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Let N(beta) be the number of beta partic...

Let `N_(beta)` be the number of `beta` particle emitted by 1 gram of `Na^(24)` radioactive nuclei hving a half life of `15 h`. In 7.5h, the number `N_(beta)` is close to
`[N_A = 6.023 xx 10^23 "mole"^(-1)]`

A

`7.5 xx 10^(21)`

B

`1.75 xx 10^(22)`

C

`6.2 xx 10^(21)`

D

`1.25 xx 10^(22)`

Text Solution

Verified by Experts

The correct Answer is:
A
No. of nuclei remains at any instant
`N= N_(0)/(2^(t//T_(1//2)))=N_(0)/sqrt(2)`
`N_("decayed")=N_(0)-N=N_(0) [1-1/sqrt(2)]`
`=1/24xx6.023xx10^(23)xx0.3`
`~~7.5xx10^(21)`
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