Home
Class 12
PHYSICS
X-ray are produced in an X-ray tube oper...

X-ray are produced in an X-ray tube operating at a given accelerating voltage. The wavelength of the continuous X-ray has values from.
(a) `0 to oo`
(b) `lambda_(min) to oo, where lambda_(min) gt 0`
(c ) 0 to `lambda_(max), where lambda_(max) ltoo`
(d) `lambda_(min) ot lambda_(max)`, where `0ltlambda(min) lt lambda_(max) lt oo`

A

`0` to `oo`

B

`lambda_("min")` to `oo` where `lambda_("min") gt 0`

C

`0` to `lambda_("max")` where `lambda_("max") lt oo`

D

`lambda_("min")` to `lambda_("max")` where `0 lt lambda_("min") lt lambda_("min") lt oo`

Text Solution

Verified by Experts

The correct Answer is:
B
The continuous X-ray specturm is shown in figure.

All wavelength `gt lambda_("min")` are found,
where `lambda_("min")=12375/("V(in volt)") Å`
Hence, V is the applied voltage.
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • SIMPLE HARMONIC MOTION

    ALLEN|Exercise MCQ s|8 Videos

  • SIMPLE HARMONIC MOTION

    ALLEN|Exercise Comprehension #1|3 Videos

  • SIMPLE HARMONIC MOTION

    ALLEN|Exercise Exercise - 04[A]|25 Videos

  • RACE

    ALLEN|Exercise Basic Maths (Wave Motion & Dopplers Effect) (Stationary waves & doppler effect, beats)|24 Videos

  • TEST PAPER

    ALLEN|Exercise PHYSICS|4 Videos

Similar Questions

Explore conceptually related problems

Show graphically the continuous of X-rays and labelling the axes and marking lambda_("min")

The minimum wavelength lambda_min in the continuous spectrum of X-rays is

Knowledge Check

  • If the equation (x^(2))/( 3 - lambda) + (y^(2))/(lambda - 8) + 1 = 0 represents an ellipse, then (i) lambda lt 8 (ii) lambda gt 3 (iii) 3 lt lambda lt 8 (iv) lambda lt 3" or "lambda gt 8

    A
    `lambda lt 8`
    B
    `lambda gt 3`
    C
    ` 3 lt lambda lt 8`
    D
    `lambda lt 3" or "lambda gt 8 `

  • Electrons with de-Broglie wavelength lambda fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-ray is

    A
    `lamda_(0)=(2mclamda^(2))/(h)`
    B
    `lamda_(0)=(2h)/(mc)`
    C
    `lamda_(0)=(2m^(2)c^(2)lamda^(2))/(h^(2))`
    D
    `lamda_(0)=lamda`

    • Similar Questions

    Explore conceptually related problems

    Electrons with de - Brogli wavelengtyh lambda fall on the target in an X-ray tube.The cut off wavelength of the emitted Xrays is (a) lambda_0 = (2mclambda^2)/(h) (b) lambda_0 = (2h)/(mc) (c ) lambda_0 (2m^2 c^2 lambda^3)/(h^2) (d) lambda_0 = lambda

    The equation of the locus of the foot of perpendicular drawn from (5, 6) on the family of lines (x-2)+lambda(y-3)=0 (where lambda in R ) is

    An X-ray tube operated at 40 k V emits a continous X-ray spectrum with a short wavelength limit lambda_(min) = 0.310 Å . Calculate Plank's constant.

    For lyman series lambda_max - lambda_min = 340 Angstrom . Find same for paschen series

    Electrons with de-Broglie wavelength lambda fall on the target in an X-ray tube. The cut-off wavelength of the emitted X-ray is

    The intensity of X-rays form a Coolidge tube is plotted against wavelength lambda as shown in the figure. The minimum wavelength found is lambda_c and the wavelength of the K_(alpha) line is lambda_k . As the accelerating voltage is increased (a) lambda_k - lambda_c increases (b) lambda_k - lambda_c decreases (c ) lambda_k increases (d) lambda_k decreases

    Home
    Profile