The mass of a nucleus `._(Z)^(A)X` is less that the sum of the masses of `(A-Z)` number of neutrons and `Z` number of protons in the nucleus.The energy equivalent to the corresponding mass difference is known as the binding energy of the nucleus. A heavy nucleus of mass `M` can break into two light nuclei of masses `m_(1)` and `m_(2)` only if `(m_(1)+m_(2)) lt M`. Also two light nuclei of masses `m_(3)` and `m_(4)` can undergo complete fusion and form a heavy nucleus of mass M'. only if `(m_(3)+m_(4)) gt M'`. The masses of some neutral atoms are given in the table below:
`|{:(._(1)^(1)H ,1.007825u , ._(1)^(2)H,2.014102u,._(1)^(3)H,3.016050u,._(2)^(4)He,4.002603u),(._(3)^(6)Li,6.015123u,._(3)^(7)Li,7.016004u,._(30)^(70)Zn,69.925325u, ._(34)^(82)Se,81.916709u),(._(64)^(152)Gd,151.91980u,._(82)^(206)Pb,205.974455u,._(83)^(209)Bi,208.980388u,._(84)^(210)Po,209.982876u):}|`
The correct statement is:

Options

A. The nucleus `._(3)^(6)Li` can emit an alpha particle
B. The nucleus `._(84)^(210)Po` can emit a proton
C. Deuteron and alpha particle can undergo complete fusion
D. The nuclei `._(30)^(70)Zn` and `._(34)^(82)Se` can undergo complete fusion

Answer

C

Explanation

Only in option (C), sum of masses of product is less then sum of masses of reactant
for reaction `._(1)(2)H+_(2)^(4)He rarr _(3)^(6)Li`.
As `M_(Li) lt M_("Deutron")+M_("alpha")`