The bob of a simple pendulum executes SHM in water with a period t. The period of oscillation of the bob in air is `t_(0)` . What is the relation between t ant `t_(0)` ?
Given, density of the bob is `(4000)/(3) kg m^(-3)` . Neglect frictional force of water.

Options

A. `t =t_(0)`
B. `t = t_(0)//2`
C. `t = 2t_(0)`
D. `t = 4t_(0)`

Explanation

The time period of a simple pendulum of density `rho` when held in a surrounding of density `sigma` is
`t_("medium") = t_(air)sqrt((rho)/(rho - sigma))`
`rArr t_("water") = t_(0)sqrt((4/3xx10^(-3))/((4/3-1)xx10^(-3))) = t_(0)sqrt((4)/(3) xx (3)/(1)) = 2t_(0)`