A solution is made by mixing `300ml 1.5M Al_(2) (SO_(4))_(3) + 300ml 2M CaSO_(4) + 400ml 3.5M CaCl_(2)`
Find final molarity of `(1) SO_(4).^(-2), (2) Ca^(2+)` (3) `Cl^(-)` [Assume complete dissociation of these compound] .

Explanation

(i) `[SO_(4)^(-2)]_(f) = ("Total moles")/("Total volume") = (300 xx 1.5 xx 10^(-3) xx 3 + 300 xx 2 xx 10^(-3))/((300 + 300 + 400)xx 10^(-3)) = 1.95 M`
(2) `[Ca^(+2)]_(f) = (300 xx 2 + 400 xx 3.5)/(1000) = 2M`
(3) `[Cl^(-)]_(f) = (400 xx 3.5 xx 2)/(1000) = 2.8 M`