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Find the mass of Free SO(3) present in 1...

Find the mass of Free `SO_(3)` present in 100gm, 109% oleum sample

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To find the mass of free SO₃ present in a 100 g sample of 109% oleum, we can follow these steps: ### Step 1: Understand the Composition of Oleum Oleum is a solution of sulfur trioxide (SO₃) in sulfuric acid (H₂SO₄). The percentage given (109%) indicates that the solution contains more SO₃ than the amount that would be present in a saturated solution. ### Step 2: Calculate the Amount of Water In a 109% oleum sample, the percentage indicates that for every 100 g of oleum, there are 9 g of water. This is derived from the fact that a 100% solution would contain only SO₃ and H₂SO₄ without any excess water. ...
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The percentage labelling (mixture of H_(2)SO_(4) and SO_(3)) refers to the total mass of pure H_(2)SO_(4) .The total amount of H_(2)SO_(4) found after adding calculated amount of water to 100 g oleum is the percentage labelling of oleum. Higher the percentage lebeling of oleum higher is the amount of free SO_(3) in the oleum sample. The percent free SO_(3) is an oleum is 20%. Label the sample of oleum in terms of percent H_(2) SO_(4) .

The percentage labelling (mixture of H_(2)SO_(4) and SO_(3)) refers to the total mass of pure H_(2)SO_(4) . The total amount of H_(2)SO_(4) found after adding calculated amount of water to 100 g oleum is the percentage labelling of oleum. Higher the percentage lebeling of oleum higher is the amount of free SO_(3) in the oleum sample. What is the amount of free SO_(3) in an oleum sample labelled as '118%'.

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