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Find the % w//v " of " ''12V'' H(2)O(2) ...

Find the `% w//v " of " ''12V'' H_(2)O_(2)` solution

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To find the % w/v (weight/volume percentage) of a 12V H₂O₂ solution, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Concept of Volume Strength**: - Volume strength (V) indicates how many volumes of oxygen are released by one volume of the solution. For H₂O₂, a 12V solution means that 1 liter of this solution will release 12 liters of oxygen. 2. **Calculate Molarity from Volume Strength**: ...
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The strength of H_(2)O_(2) is expressed in several ways like molarity, normality,% (w/V), volume strength, etc. The strength of "10 V" means 1 volume of H_(2)O_(2) on decomposition gives 10 volumes of oxygen at 1 atm and 273 K or 1 litre of H_(2)O_(2) gives 10 litre of O_(2) at 1 atm and 273 K The decomposition of H_(2)O_(2) is shown as under : H_(2)O_(2)(aq) to H_(2)O(l)+(1)/(2)O_(2)(g) H_(2)O_(2) can acts as oxidising as well as reducing agent. As oxidizing agent H_(2)O_(2) is converted into H_(2)O and as reducing agent H_(2)O_(2) is converted into O_(2) . For both cases its n-factor is 2. :. "Normality " " of " H_(2)O_(2) solution =2xx "molarity of" H_(2)O_(2) solution What is thepercentage strength (%w/V) of "11.2 V" H_(2)O_(2)

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