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(i) 2 gm H(2)SO(4) is dissolved in 38 gm...

(i) 2 gm `H_(2)SO_(4)` is dissolved in 38 gm water. Find (w/w)%

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To solve the problem of finding the weight/weight percentage (w/w%) of H₂SO₄ in a solution where 2 grams of H₂SO₄ is dissolved in 38 grams of water, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Mass of the Solute and Solvent:** - Mass of solute (H₂SO₄) = 2 grams - Mass of solvent (water) = 38 grams 2. **Calculate the Mass of the Solution:** - The mass of the solution is the sum of the mass of the solute and the mass of the solvent. - Mass of solution = Mass of solute + Mass of solvent - Mass of solution = 2 grams + 38 grams = 40 grams 3. **Use the Formula for Weight/Weight Percentage:** - The formula for weight/weight percentage is given by: \[ \text{w/w\%} = \left( \frac{\text{mass of solute}}{\text{mass of solution}} \right) \times 100 \] 4. **Substitute the Values into the Formula:** - Substitute the mass of the solute and the mass of the solution into the formula: \[ \text{w/w\%} = \left( \frac{2 \text{ grams}}{40 \text{ grams}} \right) \times 100 \] 5. **Calculate the Result:** - Calculate the fraction: \[ \frac{2}{40} = 0.05 \] - Now multiply by 100 to get the percentage: \[ 0.05 \times 100 = 5\% \] ### Final Answer: The weight/weight percentage (w/w%) of H₂SO₄ in the solution is **5%**. ---
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