5.85 gm NaCl, 4 gm MgO is dissolved in 14.4 gm of water to form a solution. Find `x_(NaCl), x_(MgO), x_(H_(2)O)`

Answer

To find the mole fractions of NaCl, MgO, and H₂O in the solution, we will follow these steps:

### Step 1: Calculate the number of moles of each component.

**For NaCl:**
- Given mass = 5.85 g
- Molar mass of NaCl = 58 g/mol
- Number of moles of NaCl (N_NaCl) = mass / molar mass = 5.85 g / 58 g/mol = 0.1 mol

**For MgO:**
- Given mass = 4 g
- Molar mass of MgO = 40 g/mol
- Number of moles of MgO (N_MgO) = mass / molar mass = 4 g / 40 g/mol = 0.1 mol

**For H₂O:**
- Given mass = 14.4 g
- Molar mass of H₂O = 18 g/mol
- Number of moles of H₂O (N_H2O) = mass / molar mass = 14.4 g / 18 g/mol = 0.8 mol

### Step 2: Calculate the total number of moles in the solution.

Total moles (N_total) = N_NaCl + N_MgO + N_H2O
= 0.1 mol + 0.1 mol + 0.8 mol = 1.0 mol

### Step 3: Calculate the mole fractions.

**For NaCl (x_NaCl):**
- Mole fraction of NaCl (x_NaCl) = N_NaCl / N_total = 0.1 mol / 1.0 mol = 0.1

**For MgO (x_MgO):**
- Mole fraction of MgO (x_MgO) = N_MgO / N_total = 0.1 mol / 1.0 mol = 0.1

**For H₂O (x_H2O):**
- Mole fraction of H₂O (x_H2O) = N_H2O / N_total = 0.8 mol / 1.0 mol = 0.8

### Final Results:
- Mole fraction of NaCl (x_NaCl) = 0.1
- Mole fraction of MgO (x_MgO) = 0.1
- Mole fraction of H₂O (x_H2O) = 0.8

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