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It was found that 20ml of water (d = 1 (...

It was found that 20ml of water `(d = 1 (gm)/(ml))` sample contains
0.5 mg of free chlorine. What is concentration of chlorine in ppm.

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To find the concentration of chlorine in parts per million (ppm), we can follow these steps: ### Step 1: Identify the mass of the solute (chlorine) We are given that the sample contains 0.5 mg of free chlorine. To work with consistent units, we convert milligrams to grams: \[ \text{Mass of chlorine} = 0.5 \, \text{mg} = 0.5 \times 10^{-3} \, \text{g} \] ### Step 2: Identify the mass of the solution (water) We are given that the volume of water is 20 ml and the density of water is 1 g/ml. Therefore, the mass of the water can be calculated as: \[ \text{Mass of water} = \text{Volume} \times \text{Density} = 20 \, \text{ml} \times 1 \, \text{g/ml} = 20 \, \text{g} \] ### Step 3: Calculate the concentration in ppm The formula for parts per million (ppm) is given by: \[ \text{ppm} = \left( \frac{\text{mass of solute}}{\text{mass of solution}} \right) \times 10^6 \] Substituting the values we have: \[ \text{ppm} = \left( \frac{0.5 \times 10^{-3} \, \text{g}}{20 \, \text{g}} \right) \times 10^6 \] ### Step 4: Simplify the expression Calculating the fraction: \[ \text{ppm} = \left( \frac{0.5 \times 10^{-3}}{20} \right) \times 10^6 = \left( \frac{0.5}{20} \times 10^{3} \right) \] \[ = \left( \frac{1}{40} \times 10^{3} \right) \] ### Step 5: Calculate the final value Calculating \( \frac{1}{40} \): \[ \frac{1}{40} = 0.025 \] Now multiply by \( 10^{3} \): \[ 0.025 \times 10^{3} = 25 \] ### Final Answer Thus, the concentration of chlorine in ppm is: \[ \text{Concentration of chlorine} = 25 \, \text{ppm} \] ---
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