How much volume of 3.0 M `H_(2)SO_(4)` is required for the preparation
of 1.0 litre of 1.0 M solution ?

Options

A. 300 ml
B. 320 ml
C. 333.3 ml
D. `350.0 ml`

Answer

To solve the problem of how much volume of 3.0 M \( H_2SO_4 \) is required to prepare 1.0 litre of 1.0 M solution, we can use the dilution equation:

\[ M_1 V_1 = M_2 V_2 \]

Where:
- \( M_1 \) = molarity of the concentrated solution (3.0 M)
- \( V_1 \) = volume of the concentrated solution (what we need to find)
- \( M_2 \) = molarity of the diluted solution (1.0 M)
- \( V_2 \) = volume of the diluted solution (1.0 L)

### Step-by-Step Solution:

1. **Identify the known values**:
- \( M_1 = 3.0 \, \text{M} \)
- \( M_2 = 1.0 \, \text{M} \)
- \( V_2 = 1.0 \, \text{L} \)

2. **Substitute the known values into the equation**:
\[ 3.0 \, \text{M} \times V_1 = 1.0 \, \text{M} \times 1.0 \, \text{L} \]

3. **Calculate \( V_1 \)**:
\[ 3.0 \, V_1 = 1.0 \]
\[ V_1 = \frac{1.0}{3.0} \, \text{L} \]
\[ V_1 = \frac{1}{3} \, \text{L} \]

4. **Convert \( V_1 \) from litres to millilitres**:
\[ V_1 = \frac{1}{3} \, \text{L} \times 1000 \, \text{mL/L} = \frac{1000}{3} \, \text{mL} \approx 333.33 \, \text{mL} \]

### Final Answer:
The volume of 3.0 M \( H_2SO_4 \) required is approximately **333.33 mL**.

---