34 g of hydrogen peroxide is present in 1135 mL of solution.
Volume strength of solution is

Options

A. 10V
B. 20V
C. 30V
D. 32V

Answer

To find the volume strength of the hydrogen peroxide solution, we will follow these steps:

### Step 1: Calculate the number of moles of hydrogen peroxide (H2O2)
We know the formula to calculate moles is:

\[ \text{Moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \]

Given:
- Mass of H2O2 = 34 g
- Molar mass of H2O2 = 34 g/mol (calculated as \(2 \times 1 + 2 \times 16 = 34\))

Now, substituting the values:

\[ \text{Moles of H2O2} = \frac{34 \, \text{g}}{34 \, \text{g/mol}} = 1 \, \text{mole} \]

### Step 2: Convert the volume of the solution from mL to L
We need to convert the volume from milliliters to liters because molarity is expressed in terms of liters.

Given:
- Volume of solution = 1135 mL

To convert to liters:

\[ \text{Volume in L} = \frac{1135 \, \text{mL}}{1000} = 1.135 \, \text{L} \]

### Step 3: Calculate the molarity of the solution
Molarity (M) is defined as the number of moles of solute per liter of solution.

\[ \text{Molarity} = \frac{\text{moles of solute}}{\text{volume of solution in L}} \]

Substituting the values:

\[ \text{Molarity} = \frac{1 \, \text{mole}}{1.135 \, \text{L}} \approx 0.88 \, \text{M} \]

### Step 4: Calculate the volume strength of the solution
The volume strength of a solution of hydrogen peroxide can be calculated using the formula:

\[ \text{Volume Strength} = 11.2 \times \text{Molarity} \]

Substituting the molarity we calculated:

\[ \text{Volume Strength} = 11.2 \times 0.88 \approx 9.856 \approx 10 \, V \]

### Final Answer
The volume strength of the solution is approximately **10 V**.

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