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10mL of 2(M) NaOH solution is added to 2...

10mL of 2(M) NaOH solution is added to 200mL of 0.5 (M) of NaOH solution. What is the final concentration?

A

0.57M

B

5.7M

C

11.4M

D

1.14M

Text Solution

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The correct Answer is:
To find the final concentration of the NaOH solution after mixing two different concentrations, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the given values:** - Volume of the first solution (V1) = 10 mL - Molarity of the first solution (M1) = 2 M - Volume of the second solution (V2) = 200 mL - Molarity of the second solution (M2) = 0.5 M 2. **Convert volumes to liters:** - V1 = 10 mL = 10/1000 L = 0.01 L - V2 = 200 mL = 200/1000 L = 0.2 L 3. **Calculate the total volume (V_final):** - V_final = V1 + V2 = 0.01 L + 0.2 L = 0.21 L 4. **Calculate the total moles of NaOH from both solutions:** - Moles from the first solution = M1 × V1 = 2 M × 0.01 L = 0.02 moles - Moles from the second solution = M2 × V2 = 0.5 M × 0.2 L = 0.1 moles 5. **Calculate the total moles of NaOH:** - Total moles = Moles from first solution + Moles from second solution - Total moles = 0.02 moles + 0.1 moles = 0.12 moles 6. **Calculate the final concentration (M_final):** - M_final = Total moles / V_final - M_final = 0.12 moles / 0.21 L = 0.5714 M 7. **Round to two decimal places:** - Final concentration ≈ 0.57 M ### Final Answer: The final concentration of the mixed NaOH solution is approximately **0.57 M**.
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