Home
Class 12
CHEMISTRY
What mass of Na(2)SO(4).7H(2)O contains ...

What mass of `Na_(2)SO_(4).7H_(2)O` contains exactly `6.023 xx 10^(22)` atoms of oxygen ? .

Text Solution

Verified by Experts

Molar mass of `Na_(2)SO_(4).7H_(2)O` =275 gm
1 mole `Na_(2)SO_(4).7H_(2)O` has 11 mol O-atoms.
`implies 11 N_(A)O`- atoms are in 275 g `Na_(2)SO_(4).7H_(2)O`
`implies 6.023xx10^(23)O`- atoms are in `=(275)/(11xx6.023xx10^(23))xx6.023xx10^(22)` g=2.5 g
Promotional Banner

Topper's Solved these Questions

  • MOLE CONCEPT

    ALLEN|Exercise Some Solved Examples|9 Videos

  • MOLE CONCEPT

    ALLEN|Exercise Basic Exercise|29 Videos

  • METALLURGY

    ALLEN|Exercise EXERCISE-05 [B]|26 Videos

  • p-Block Element

    ALLEN|Exercise All Questions|20 Videos

Similar Questions

Explore conceptually related problems

6.023 xx 10^(22) atoms of Hydrogen can make

What mass of H_(2)SO_(4) contains 32g oxygen ? .

1.61 gm of Na_(2)SO_(4). 10H_(2)O contains same number of oxygen atoms as present in:

Na_(2)SO_(4).xH_(2)O has 50% H_(2)O . Henxe, x is :

13.4 g of a sample of unstable hydrated salt Na_(2)SO_(4).XH_(2)O was found to contains 6.3 g of H_(2) O . The number of molecular of water of crystalistion is

Structure of Na_(2)[B_(4)O_(5)(OH)_(4)]*8H_(2)O contains

A sample of MgSO_(4) has 6.023 xx 10^(20)O atoms What is mass of Mg in sample ? .

26.8 gm Na_(2)SO_(4). nH_(2)O contains 12.6 of water here the value of 'n' is ?

Consider the following equation H_(4)P_(2)O_(7) + 2NaOH to Na_(2)H_(2)P_(2)O_(7) + 2H_(2)O If 534 gm of H_(4)P_(2)O_(7) is reacted with 3.0 xx 10^(24) formula units of NaOH ,then total number of moles of H_(2)O is produced is ( N_(A) = 6 xx 10^(23) )

Na_(2)B_(4)O_(7).10H_(2)O is correctly represented as