28 gm lithium is mixed with 48 gm `O_(2)` to reacts according to the following reaction.
`4Li + O_(2) to 2Li_(2)O`
The mass of `Li_(2)O` formed is

Explanation

To solve the problem step by step, we will follow these calculations:

### Step 1: Write down the balanced chemical equation.
The balanced chemical equation for the reaction is:
\[ 4 \text{Li} + \text{O}_2 \rightarrow 2 \text{Li}_2\text{O} \]

### Step 2: Calculate the moles of lithium (Li) and oxygen (O₂).
- Molar mass of lithium (Li) = 7 g/mol
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