`1.5gm` mixture of `SiO_(2)` and `Fe_(2)O_(3)` on very strong heating leave a residue weighting `1.46gm`. The reaction responsible for loss of weight is . `Fe_(2) O_(3) (s) rarr Fe_(3)O_(4) (s) + O_(2)(g)` What is the percentage by mass of `Fe_(2)O_(3)` is original sample .
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`3Fe_(2)O_(3) to 2Fe_(3)O_(4) + (1)/(2)O_(2)` `3xx160 " "(1)/(2)xx32` `=480 gm to " "=16 gm` loss of 16 gm `to 480` gm `Fe_(2)O_(3)` loss of 0.04 gm `to 0.04xx(480)/(16)=1.2` gm `Fe_(2)O_(3)` `%` by mass `=(1.2)/(1.5)xx100=80%`
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