A sample of 0.50 g of an organic compound was treated according to Kjeldahl's method. The ammonia evolved was absorbed in 50 mL of 0.5 M `H_(2)SO_(4)`. The residual acid required 60 mL of 0.5 M solution of NaOH for neutralisation. What would be the percentage composition of nitrogen in the compound?
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`2NH_(3) + H_(2)SO_(4) to (NH_(4))_(2)SO_(4)` `H_(2)SO_(4) + 2NaOH to Na_(2)SO_(4) + 2H_(2)O` m mol of `H_(2)SO_(4)` used to react with NaOH `=(0.6)/(40)=15` m mol Remaining mmol of `H_(2)SO_(4)=(2.45)/(98)xx10^(3)-15=10` mmol of `NH_(3)` used=`10xx2=20` % N in sample `=(20xx10^(-3)xx14)/(0.5)xx100=56%`
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