The empirical formula of an organic compound carbon & hydrogen is `CH_(2)` The mass of `1"litre"` of organic gas is exactly equal to mass of 1 litre `N_(2)` therefore molecular formula of organic gas is .
Text Solution
Verified by Experts
Empirical Mass of `CH_(3)=12+2=14` `because` Mass of 1 litre of organic gas = Mass of 1 litre of `N_(2)` Since V,P,T, n are same. Therefore PV=`(m)/(M)RT` implies that molar mass should also be same. `therefore ` Molecular mass of organic compound will be 28 g `n=("Molecular mass")/("Empirical mass")=(28)/(14)=2` So molecular formula `=2xxCH_(2) =C_(2)H_(4)`
Topper's Solved these Questions
MOLE CONCEPT
ALLEN|Exercise Some Solved Examples|9 Videos
MOLE CONCEPT
ALLEN|Exercise Basic Exercise|29 Videos
METALLURGY
ALLEN|Exercise EXERCISE-05 [B]|26 Videos
p-Block Element
ALLEN|Exercise All Questions|20 Videos
Similar Questions
Explore conceptually related problems
If the molecular formula of an organic compound is C_(2)H_(2) it is :
The empirical formula of a compound of molecular mass 120 is CH_(2)O . The molecular formula of the compound is :
If the molecular formula of an organic compound is C_10H_18 . It is:
The molecular formula of an organic compound is C6H12O6 and the empirical formula is CH2O the value of n is
The empirical formula of a compound is CH_2O_2 . What could be its molecular formula?
The empirical formula of a compound is CH_2O and its vapour density is 30. The molecular formula of the compound is:
1 litre of a hydrocarbon weight as much as one litre of CO_(2) . The molecular formula of hydrocarbon is :-
The mass of 5.6 litres of a certain gas at S.T .P. is 12 g. What is the relative molecular mass or molar mass of the gas ?
