Calculate mass of O atoms in 8 gm `CH_(3)COOH` ?

Answer

To calculate the mass of oxygen atoms in 8 grams of acetic acid (CH₃COOH), we can follow these steps:

### Step 1: Calculate the molar mass of CH₃COOH.
The molar mass is calculated by adding the atomic masses of all the atoms in the molecule:
- Carbon (C): 12 g/mol (2 Carbons) = 2 × 12 = 24 g/mol
- Hydrogen (H): 1 g/mol (4 Hydrogens) = 4 × 1 = 4 g/mol
- Oxygen (O): 16 g/mol (2 Oxygens) = 2 × 16 = 32 g/mol

Adding these together:
\[ \text{Molar mass of CH}_3\text{COOH} = 24 + 4 + 32 = 60 \text{ g/mol} \]

### Step 2: Calculate the number of moles of CH₃COOH in 8 grams.
Using the formula:
\[ \text{Number of moles} = \frac{\text{mass}}{\text{molar mass}} \]
Substituting the values:
\[ \text{Number of moles of CH}_3\text{COOH} = \frac{8 \text{ g}}{60 \text{ g/mol}} = 0.1333 \text{ moles} \approx 0.13 \text{ moles} \]

### Step 3: Determine the number of moles of oxygen atoms.
Since each molecule of CH₃COOH contains 2 oxygen atoms, the number of moles of oxygen atoms is:
\[ \text{Moles of O} = 2 \times \text{moles of CH}_3\text{COOH} = 2 \times 0.13 = 0.26 \text{ moles} \]

### Step 4: Calculate the mass of oxygen atoms.
Using the formula:
\[ \text{Mass} = \text{moles} \times \text{atomic mass} \]
Substituting the values:
\[ \text{Mass of O} = 0.26 \text{ moles} \times 16 \text{ g/mol} = 4.16 \text{ g} \]

### Final Answer:
The mass of oxygen atoms in 8 grams of CH₃COOH is **4.16 grams**.

---