the Kohinoor diamond was the largest diamond ever found . How many moles of carbon atom were present in it , if it is weight 3300 carat. [Given :1 carat = 200 mg ]

Answer

To find the number of moles of carbon atoms present in the Kohinoor diamond weighing 3300 carats, we can follow these steps:

### Step 1: Convert carats to milligrams
Given that 1 carat = 200 mg, we can convert the weight of the diamond from carats to milligrams.

\[ \text{Weight in mg} = \text{Weight in carats} \times 200 \text{ mg/carat} \]

\[ \text{Weight in mg} = 3300 \text{ carats} \times 200 \text{ mg/carat} = 660000 \text{ mg} \]

### Step 2: Convert milligrams to grams
Since 1000 mg = 1 g, we can convert the weight from milligrams to grams.

\[ \text{Weight in grams} = \frac{\text{Weight in mg}}{1000} \]

\[ \text{Weight in grams} = \frac{660000 \text{ mg}}{1000} = 660 \text{ g} \]

### Step 3: Calculate the number of moles of carbon
To find the number of moles, we use the formula:

\[ \text{Number of moles} = \frac{\text{Weight in grams}}{\text{Molar mass of carbon}} \]

The molar mass of carbon is approximately 12 g/mol.

\[ \text{Number of moles} = \frac{660 \text{ g}}{12 \text{ g/mol}} = 55 \text{ moles} \]

### Final Answer
The number of moles of carbon atoms present in the Kohinoor diamond is **55 moles**.

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