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The number of electron in 3.1 mg NO(3)^(...

The number of electron in `3.1 mg NO_(3)^(-)` is (`N_(A)` = `6 xx 10^(23)` )

A

32

B

`1.6xx10^(-3)`

C

`9.6xx 10^(20)`

D

`9.6xx10^(23)`

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The correct Answer is:
C
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