1 mole of `H_(2)SO_(4)` will exactly neutralise:

Options

A. 2 mole of ammonia
B. 1 mole of `Ba(OH)_(2)`
C. 0.5 mole of `Ca(OH)_(2)`
D. 2 mole of KOH

Answer

To solve the problem of how many moles of different bases can be neutralized by 1 mole of sulfuric acid (H₂SO₄), we need to understand the concept of gram equivalents and how they relate to neutralization reactions.

### Step-by-Step Solution:

1. **Identify the Acid and Its Properties**:
- We have 1 mole of sulfuric acid (H₂SO₄).
- H₂SO₄ is a diprotic acid, meaning it can donate 2 protons (H⁺ ions) per molecule.

2. **Calculate the Number of Gram Equivalents of H₂SO₄**:
- Since 1 mole of H₂SO₄ can donate 2 moles of H⁺, the number of gram equivalents of H₂SO₄ is:
\[ \text{Gram equivalents of H₂SO₄} = 1 \text{ mole} \times 2 = 2 \text{ equivalents} \]

3. **Analyze Each Option**:
- **Option A: 2 moles of NH₃ (Ammonia)**:
- Each mole of NH₃ can accept 1 H⁺, so:
\[ \text{Gram equivalents} = 2 \text{ moles} \times 1 = 2 \text{ equivalents} \]
- This option is valid as it matches the 2 equivalents from H₂SO₄.

- **Option B: 1 mole of Ba(OH)₂ (Barium Hydroxide)**:
- Each mole of Ba(OH)₂ produces 2 OH⁻ ions, so:
\[ \text{Gram equivalents} = 1 \text{ mole} \times 2 = 2 \text{ equivalents} \]
- This option is also valid.

- **Option C: 0.5 moles of Ca(OH)₂ (Calcium Hydroxide)**:
- Each mole of Ca(OH)₂ produces 2 OH⁻ ions, so:
\[ \text{Gram equivalents} = 0.5 \text{ moles} \times 2 = 1 \text{ equivalent} \]
- This option is invalid as it does not match the 2 equivalents from H₂SO₄.

- **Option D: 2 moles of KOH (Potassium Hydroxide)**:
- Each mole of KOH produces 1 OH⁻ ion, so:
\[ \text{Gram equivalents} = 2 \text{ moles} \times 1 = 2 \text{ equivalents} \]
- This option is valid.

4. **Conclusion**:
- The valid options that can be neutralized by 1 mole of H₂SO₄ are:
- 2 moles of NH₃
- 1 mole of Ba(OH)₂
- 2 moles of KOH
- The incorrect option is 0.5 moles of Ca(OH)₂.

### Final Answer:
1 mole of H₂SO₄ will exactly neutralize:
- 2 moles of NH₃
- 1 mole of Ba(OH)₂
- 2 moles of KOH