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Select the correct statement(s) for (NH(...

Select the correct statement(s) for `(NH_(4))_(3)PO_(4)`

A

Ratio of number of oxygen atoms to number of hydrogen atoms is 1:3

B

Ratio of number of cations to number of anions is 3:1

C

Ratio of number of gm-atoms of nitrogen to gm-atoms of oxygen is 3:2

D

Total number of atoms in one mole of `(MH_(4))_(3)PO_(4)` is 20.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the compound ammonium phosphate, \((NH_4)_3PO_4\), we will analyze each statement provided. ### Step-by-Step Solution: 1. **Identify the number of atoms in ammonium phosphate**: - The formula \((NH_4)_3PO_4\) indicates that there are: - 3 ammonium ions, each containing 4 hydrogen atoms (total: \(3 \times 4 = 12\) hydrogen atoms). - 1 phosphate ion, which contains 4 oxygen atoms. - Therefore, in one molecule of ammonium phosphate, we have: - Hydrogen (H): 12 - Oxygen (O): 4 2. **Calculate the ratio of oxygen to hydrogen**: - The ratio of the number of oxygen atoms to the number of hydrogen atoms is: \[ \text{Ratio} = \frac{\text{Number of O atoms}}{\text{Number of H atoms}} = \frac{4}{12} = \frac{1}{3} \] - **Conclusion**: The first statement is correct. 3. **Determine the ratio of cations to anions**: - In ammonium phosphate, the cation is ammonium \((NH_4^+)\) and the anion is phosphate \((PO_4^{3-})\). - There are 3 ammonium cations for every 1 phosphate anion. - Therefore, the ratio of cations to anions is: \[ \text{Ratio} = \frac{3 \text{ (cations)}}{1 \text{ (anion)}} = 3:1 \] - **Conclusion**: The second statement is also correct. 4. **Calculate the ratio of gram atoms of nitrogen to gram atoms of oxygen**: - In \((NH_4)_3PO_4\): - There are 3 nitrogen atoms (from 3 ammonium ions). - There are 4 oxygen atoms (from the phosphate ion). - The ratio of the number of gram atoms of nitrogen to the number of gram atoms of oxygen is: \[ \text{Ratio} = \frac{3 \text{ (N atoms)}}{4 \text{ (O atoms)}} = \frac{3}{4} \] - **Conclusion**: The third statement is incorrect (it claims a ratio of \(3:2\)). 5. **Calculate the total number of atoms in one mole of ammonium phosphate**: - Each molecule of ammonium phosphate contains: - 3 nitrogen (N) + 12 hydrogen (H) + 1 phosphorus (P) + 4 oxygen (O) = 20 atoms in total. - Therefore, in one mole (which is \(6.022 \times 10^{23}\) molecules), the total number of atoms is: \[ 20 \text{ (atoms per molecule)} \times 6.022 \times 10^{23} \text{ (molecules)} = 20N_a \] - **Conclusion**: The fourth statement is incorrect (it claims a total of 20 atoms instead of \(20N_a\)). ### Final Answer: The correct statements are: - Statement A: Correct (Ratio of O to H is \(1:3\)) - Statement B: Correct (Ratio of cations to anions is \(3:1\)) - Statement C: Incorrect (Ratio of N to O is \(3:4\)) - Statement D: Incorrect (Total number of atoms is \(20N_a\))
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