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Comprehension # 3 NaBr, used to produ...

Comprehension # 3
`NaBr`, used to produce `AgBr` for use in photography can be self prepared as follows :
`{:(,Fe+Br_(2)rarrFeBr_(2)," "..........(i),),(,FeBr_(2)+Br_(2)rarrFe_(3)Br_(8)," " ..........(ii) ," "("not balanced")),(,Fe_(3)Br_(8)+Na_(2)CO_(3)rarrNaBr+CO_(2)+Fe_(3)O_(4) , " ".......(iii)," "("not balanced")):}`
How much `Fe` in `kg` is consumed to produce `2.06xx10^(3) kg Nabr " "........(iv)`
If yield of `(iii)` reaction is `90%` then mole of `CO_(2)` formed when `2.06xx10^(3) kg NaBr` is formed.

A

20

B

10

C

9

D

440

Text Solution

Verified by Experts

The correct Answer is:
B
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Comprehension # 3 NaBr , used to produce AgBr for use in photography can be self prepared as follows : {:(,Fe+Br_(2)rarrFeBr_(2)," "..........(i),),(,FeBr_(2)+Br_(2)rarrFe_(3)Br_(8)," " ..........(ii) ," "("not balanced")),(,Fe_(3)Br_(8)+Na_(2)CO_(3)rarrNaBr+CO_(2)+Fe_(3)O_(4) , " ".......(iii)," "("not balanced")):} How much Fe in kg is consumed to produce 2.06xx10^(3) kg Nabr " "........(iv) Mass of iron required to produce 2.06xx10^(3) kg NaBr

Comprehension # 3 NaBr , used to produce AgBr for use in photography can be self prepared as follows : {:(,Fe+Br_(2)rarrFeBr_(2)," "..........(i),),(,FeBr_(2)+Br_(2)rarrFe_(3)Br_(8)," " ..........(ii) ," "("not balanced")),(,Fe_(3)Br_(8)+Na_(2)CO_(3)rarrNaBr+CO_(2)+Fe_(3)O_(4) , " ".......(iii)," "("not balanced")):} If the yield of (ii) is 60% & (iii) reaction is 70% then mass of ion required to produce 2.06xx10^(3) kg NaBr .

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