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The number of oxygen atoms present in 24...

The number of oxygen atoms present in 24.5 gm of `H_(3)PO_(4)` is equal to (P = 31)

A

(a)Number of electrons present in 1.6 gm methane `(CH_(4))`

B

(b)Number of molecule of `CO_(2)` present in 22 gm `CO_(2)`

C

(c)Number of moles of proton present in `N_(A) gm`-atom of hydrogen.

D

(d)Number of total atoms present in `(4)/(3)` mol of `CO_(2)`

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