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If (5+2sqrt6)^(x^(2)-8)+(5-2sqrt6)^(x^(2...

If `(5+2sqrt6)^(x^(2)-8)+(5-2sqrt6)^(x^(2)-8)=10, x inR`
On the basis of above information, answer the following questions :
Number of solution (s) of the given equation is/ are -

A

1

B

2

C

4

D

infinte

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \((5 + 2\sqrt{6})^{x^{2}-8} + (5 - 2\sqrt{6})^{x^{2}-8} = 10\), we will follow these steps: ### Step 1: Define Variables Let \( y = x^2 - 8 \). Then, the equation can be rewritten as: \[ (5 + 2\sqrt{6})^y + (5 - 2\sqrt{6})^y = 10 \] ### Step 2: Analyze the Terms Notice that \( 5 + 2\sqrt{6} \) and \( 5 - 2\sqrt{6} \) are conjugates. The term \( 5 + 2\sqrt{6} \) is greater than 1, while \( 5 - 2\sqrt{6} \) is less than 1 because \( 5 - 2\sqrt{6} \approx 0.1 \). ### Step 3: Properties of the Function The function \( f(y) = (5 + 2\sqrt{6})^y + (5 - 2\sqrt{6})^y \) is continuous and strictly increasing for \( y \in \mathbb{R} \) because the first term increases and the second term decreases as \( y \) increases. ### Step 4: Find Values of \( y \) We need to find the values of \( y \) such that: \[ f(y) = 10 \] Since \( f(y) \) is continuous and strictly increasing, it will intersect the line \( y = 10 \) at most once. ### Step 5: Check Specific Values Let's check \( y = 1 \) and \( y = -1 \): 1. For \( y = 1 \): \[ f(1) = (5 + 2\sqrt{6})^1 + (5 - 2\sqrt{6})^1 = (5 + 2\sqrt{6}) + (5 - 2\sqrt{6}) = 10 \] So, \( y = 1 \) is a solution. 2. For \( y = -1 \): \[ f(-1) = (5 + 2\sqrt{6})^{-1} + (5 - 2\sqrt{6})^{-1} \] This can be calculated as: \[ f(-1) = \frac{1}{5 + 2\sqrt{6}} + \frac{1}{5 - 2\sqrt{6}} \] Rationalizing gives: \[ f(-1) = \frac{(5 - 2\sqrt{6}) + (5 + 2\sqrt{6})}{(5 + 2\sqrt{6})(5 - 2\sqrt{6})} = \frac{10}{25 - 24} = 10 \] So, \( y = -1 \) is also a solution. ### Step 6: Solve for \( x \) Now we have two values for \( y \): 1. \( y = 1 \) gives: \[ x^2 - 8 = 1 \implies x^2 = 9 \implies x = \pm 3 \] 2. \( y = -1 \) gives: \[ x^2 - 8 = -1 \implies x^2 = 7 \implies x = \pm \sqrt{7} \] ### Step 7: Count the Solutions Thus, we have four solutions: - \( x = 3 \) - \( x = -3 \) - \( x = \sqrt{7} \) - \( x = -\sqrt{7} \) ### Final Answer The number of solutions of the given equation is **4**. ---
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