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If sin2A= lambda sin 2B prove that (tan...

If ` sin2A= lambda sin 2B` prove that `(tan(A+B)/tan(A-B))=(lambda+1)/(lambda-1)`

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To prove that if \( \sin 2A = \lambda \sin 2B \), then \[ \frac{\tan(A+B)}{\tan(A-B)} = \frac{\lambda + 1}{\lambda - 1} \] we can follow these steps: ...
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