Given `vecF=(veca)/(t)` where symbols have their usual meaning. The dimensions of a is .

Answer

To find the dimensions of \( \vec{a} \) given the equation \( \vec{F} = \frac{\vec{a}}{t} \), we can follow these steps:

### Step 1: Rearranging the equation
We start with the equation:
\[ \vec{F} = \frac{\vec{a}}{t} \]
To find \( \vec{a} \), we can rearrange the equation:
\[ \vec{a} = \vec{F} \cdot t \]

### Step 2: Identifying the dimensions of force
Next, we need to identify the dimensions of force \( \vec{F} \). The dimension of force is given by:
\[ [\vec{F}] = [M][L][T^{-2}] \]
This means that the dimensions of force are:
\[ [\vec{F}] = M L T^{-2} \]

### Step 3: Identifying the dimensions of time
Now, we identify the dimensions of time \( t \):
\[ [t] = T \]

### Step 4: Combining the dimensions
Now we can substitute the dimensions of \( \vec{F} \) and \( t \) back into our rearranged equation for \( \vec{a} \):
\[ [\vec{a}] = [\vec{F}] \cdot [t] = (M L T^{-2}) \cdot (T) \]

### Step 5: Simplifying the dimensions
Now we simplify the expression:
\[ [\vec{a}] = M L T^{-2} \cdot T = M L T^{-1} \]

### Final Result
Thus, the dimensions of \( \vec{a} \) are:
\[ [\vec{a}] = M L T^{-1} \]