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In a certain system of units, 1 unit of ...

In a certain system of units, 1 unit of time is 5 sec, 1 unit of mass is 20 kg and 1 uint of length is 10m. In this system, one unit of power will correspond to :-

A

16 watts

B

`(1)/(16)` watts

C

25 watts

D

none of these.

Text Solution

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The correct Answer is:
To find one unit of power in the given system of units, we will follow these steps: ### Step 1: Understand the formula for power Power (P) is defined as the work done (W) per unit of time (t). Mathematically, this is expressed as: \[ P = \frac{W}{t} \] ### Step 2: Relate work done to force and displacement Work done is defined as the product of force (F) and displacement (d): \[ W = F \cdot d \] And force is defined as mass (m) times acceleration (a): \[ F = m \cdot a \] Thus, we can express power as: \[ P = \frac{F \cdot d}{t} = \frac{m \cdot a \cdot d}{t} \] ### Step 3: Identify the units in the given system According to the problem: - 1 unit of time = 5 seconds - 1 unit of mass = 20 kg - 1 unit of length = 10 m ### Step 4: Substitute the units into the power formula We need to express acceleration (a) in terms of the given units. Acceleration is defined as: \[ a = \frac{d}{t^2} \] Using the units provided: - Displacement (d) = 10 m (1 unit of length) - Time (t) = 5 s (1 unit of time) Thus, the acceleration in the given units can be calculated as: \[ a = \frac{10 \, \text{m}}{(5 \, \text{s})^2} = \frac{10}{25} = 0.4 \, \text{m/s}^2 \] ### Step 5: Substitute the values into the power formula Now we can substitute the values into the power equation: \[ P = \frac{m \cdot a \cdot d}{t} \] Substituting the known values: \[ P = \frac{(20 \, \text{kg}) \cdot (0.4 \, \text{m/s}^2) \cdot (10 \, \text{m})}{5 \, \text{s}} \] ### Step 6: Calculate the power Now we can compute the power: \[ P = \frac{20 \cdot 0.4 \cdot 10}{5} \] Calculating the numerator: \[ 20 \cdot 0.4 = 8 \] \[ 8 \cdot 10 = 80 \] Now divide by the denominator: \[ P = \frac{80}{5} = 16 \] ### Step 7: Conclusion Thus, one unit of power in this system corresponds to: \[ \text{1 unit of power} = 16 \, \text{W} \]
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