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Which of the following species is most b...

Which of the following species is most basic and have NO back bonding ?

A

`P(SiH_(3))_(3)`

B

`N(CH_(3))_(3)`

C

`N(SiH_(3))_(3)`

D

`BCl_(3)`

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The correct Answer is:
To determine which of the given species is the most basic and has no back bonding, we will analyze each option step by step. ### Step 1: Understand Basicity Basicity refers to the ability of a species to donate a lone pair of electrons. A more basic species has a higher tendency to donate its lone pair. ### Step 2: Identify Back Bonding Back bonding occurs when there is a partial double bond character due to the donation of electron density from a filled orbital of one atom to an empty orbital of another atom. This can reduce the availability of lone pairs for donation, thus decreasing basicity. ### Step 3: Analyze Each Option 1. **Option A: Phosphorus connected to Silicon Hydrides (SiH₄)** - Phosphorus has a lone pair of electrons. - Silicon has empty d-orbitals, which can accept electron density from phosphorus. - This leads to back bonding, which decreases the basicity of phosphorus in this compound. 2. **Option B: Nitrogen connected to three Methyl groups (CH₃)** - Nitrogen has a lone pair of electrons. - Carbon does not have empty d-orbitals to accept electron density. - The methyl groups are electron-donating (inductive effect), which increases the electron density on nitrogen. - There is no back bonding because carbon lacks empty orbitals, making this species more basic. 3. **Option C: Nitrogen connected to Silicon Hydrides (SiH₄)** - Similar to option A, nitrogen has a lone pair. - Silicon can accept electron density due to its empty d-orbitals, leading to back bonding. - This decreases the basicity of nitrogen in this compound. 4. **Option D: Boron connected to Chlorine (Cl) and Bromine (Br)** - Boron has an empty p-orbital and is electron-deficient. - Chlorine and bromine can donate electron density, but boron cannot effectively donate a lone pair due to its deficiency. - There may be some back bonding due to the empty p-orbital of boron, but boron is not basic. ### Step 4: Conclusion After analyzing all options, we find that: - **Option B** (Nitrogen connected to three methyl groups) is the most basic and has no back bonding due to the absence of empty orbitals in carbon. ### Final Answer **Option B is the most basic and has no back bonding.** ---
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