Drawn the structure of the following:
(i) `H_(3)PO_(2)`
(ii) `XeF_(4)`

Draw the structures of the following: H_(3)PO_(3)

Drawn the structure of the following (i) H_(2)S_(2)O_(7) (ii) XeF_(6)

(a) Complete the following chemical equations : (i) NaOH + Cl_(2) rarr ("hot and cone.") (ii) XeF_(4) + O_(2)F_(2)rarr (b) Draw the structure of the following molecules : (i) H_(3)PO_(2) (ii) H_(2)S_(2)O_(7) (ii) XeOF_(4)

Write the structure of the following : (i) BrF_(3) (ii) XeF_(4)

Draw the structure of the following : (i) XeF_(2) (ii) BrF_(3)

Draw the structure of the following : (i) XeF_(2) (ii) BrF_(3)

Draw the structure of the following : (i) H_2SO_4 (ii) XeF_2

Draw the structures of the following molecules : (i) SF_(4) (ii) XeF_(4)

Draw the structures of the following molecules : (i) N_(2)O_(5) (ii) XeF_(2)

(a) Give reasons : (i) H_(3)PO_(3) undergoes disproportionation reaction but H_(3)PO_(4) does not . (ii) When Cl_(2) reacts with excess of F_(2), ClF_(3) is formed and not FCl_(3) . (iii) Dioxygen is a gas while Sulphur is a solid at room temperature . (b) Draw the structure of the following : (i) XeF_(4) " " (ii) HClO_(3)