If two moles of Isopropyl chloride reacts with `Na` presence of dry ether. Which alkane is obtained.

Explanation

To solve the question of what alkane is obtained when two moles of isopropyl chloride react with sodium in the presence of dry ether, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant is isopropyl chloride, which has the molecular formula \( \text{C}_3\text{H}_7\text{Cl} \) or can be represented as \( \text{CH}_3\text{CHClCH}_3 \).

2. **Understand the Reaction Type**:
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