Sodium propionate on decarboxylation with sodalime gives

Options

A. Propane
B. Ethane
C. Butane
D. Pentane

Explanation

To solve the question regarding the decarboxylation of sodium propionate with soda lime, we can break down the process step by step.

### Step-by-Step Solution:

1. **Understanding Decarboxylation**:
Decarboxylation is the process of removing a carboxyl group (-COOH) from a compound, releasing carbon dioxide (CO2). In this case, we are dealing with sodium propionate, which is the sodium salt of propanoic acid.

2. **Chemical Structure of Sodium Propionate**:
Sodium propionate can be represented as CH3CH2COONa. It consists of a propionate ion (CH3CH2COO-) and sodium ion (Na+).

3. **Reaction with Soda Lime**:
Soda lime is a mixture of sodium hydroxide (NaOH) and calcium oxide (CaO). When sodium propionate is treated with soda lime, the sodium hydroxide acts as a strong base that facilitates the decarboxylation process.

4. **Decarboxylation Reaction**:
The reaction can be represented as follows:
\[ \text{CH}_3\text{CH}_2\text{COONa} \xrightarrow{\text{soda lime}} \text{CH}_3\text{CH}_2\text{CH}_3 + \text{Na}_2\text{CO}_3 \]
Here, sodium propionate loses a carbon dioxide molecule (CO2) and forms propane (CH3CH2CH3).

5. **Final Product**:
The final product of the decarboxylation of sodium propionate with soda lime is propane (C3H8).

### Conclusion:
Thus, sodium propionate on decarboxylation with soda lime gives propane.

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