`10 mL` of a mixture of `CH_(4)` and `C_(3)H_(8)` requires `41 mL` of oxygen for complete combustion. What is the volume of `CH_(4)` and `C_(3)H_(8)` in. the mixture.

Explanation

To solve the problem, we need to determine the volumes of methane (CH₄) and propane (C₃H₈) in a 10 mL mixture that requires 41 mL of oxygen for complete combustion.

### Step-by-Step Solution:

1. **Define Variables**:
Let the volume of methane (CH₄) in the mixture be \( x \) mL. Therefore, the volume of propane (C₃H₈) will be \( 10 - x \) mL since the total volume of the mixture is 10 mL.

2. **Write the Combustion Reactions**:
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