If `5g C_(2)H_(5)I` reacts with `Na` (metallic) in presence of ether, and the yield is `60%` then how many grams of n-butane will you get

Explanation

To solve the problem step by step, we will follow the reaction of ethyl iodide (C2H5I) with sodium (Na) in the presence of ether to produce n-butane (C4H10) and sodium iodide (NaI).

### Step-by-Step Solution:

1. **Write the Reaction**:
The reaction of ethyl iodide with sodium can be represented as:
\[
2 \text{C}_2\text{H}_5\text{I} + 2 \text{Na} \xrightarrow{\text{ether}} \text{C}_4\text{H}_{10} + 2 \text{NaI}
...