`30 mL` mixture of ethylene and Butylene is burnt in presence of oxygen then `150mL` of oxygen is required, what is the volume of Ethylene `&` Butylene in mixture.

Explanation

To solve the problem, we need to determine the volumes of ethylene (C2H4) and butylene (C4H8) in a 30 mL mixture that requires 150 mL of oxygen for combustion.

### Step-by-Step Solution:

1. **Define Variables**:
- Let the volume of ethylene (C2H4) in the mixture be \( x \) mL.
- Therefore, the volume of butylene (C4H8) will be \( 30 - x \) mL (since the total volume of the mixture is 30 mL).

...