How much propanol is required for dehydration to get `2.24` litre of propene at `N.T.P`. If yield is `100%`

Explanation

To solve the problem of how much propanol is required for dehydration to obtain 2.24 liters of propene at N.T.P (Normal Temperature and Pressure), we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Reaction**:
The dehydration of propanol (C3H8O) produces propene (C3H6) and water (H2O). The balanced chemical equation for the reaction is:
\[
C3H8O \xrightarrow{H2SO4} C3H6 + H2O
...