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R-CH(2)-C Cl(2)-R overset(Reag ent)rarrR...

`R-CH_(2)-C Cl_(2)-R overset(Reag ent)rarrR-C-=C-R`
The reagent used is

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To solve the problem of transforming R-CH₂-CCl₂-R into R-C≡C-R, we need to identify the reagents used in this reaction. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the Starting Compound The starting compound is R-CH₂-CCl₂-R, which is a 1,1-dihaloalkane. This compound contains two chlorine atoms attached to a carbon atom that is also connected to two R groups. **Hint:** Look for the functional groups and the structure of the starting compound to understand what kind of reactions it can undergo. ### Step 2: First Reagent - Alcoholic KOH The first reagent used is alcoholic KOH. When this reagent is added to the 1,1-dihaloalkane, it initiates a dehydrohalogenation reaction. This means that one of the chlorine atoms will be removed along with a hydrogen atom from the adjacent carbon, leading to the formation of a double bond. **Hint:** Remember that alcoholic KOH is commonly used for elimination reactions to form alkenes by removing halogens and hydrogens. ### Step 3: Formation of an Alkene After the reaction with alcoholic KOH, we form R-CH=CR. This is an alkene where one chlorine atom has been eliminated, resulting in a double bond between the two carbon atoms. **Hint:** Keep track of the changes in the molecular structure after the elimination of the halogen. ### Step 4: Second Reagent - Sodium Amide (NaNH₂) The next step involves the addition of sodium amide (NaNH₂). This reagent is also a strong base and will further facilitate the elimination of the remaining hydrogen halide (HCl) from the alkene formed in the previous step. **Hint:** Sodium amide is often used in reactions to generate alkynes from alkenes by removing hydrogen halides. ### Step 5: Formation of Alkyne The final product after the reaction with NaNH₂ is R-C≡C-R, which is an alkyne. This occurs through the removal of HCl, resulting in the formation of a triple bond between the two carbon atoms. **Hint:** Recognize that the transformation from an alkene to an alkyne involves the removal of a hydrogen halide, leading to the formation of a triple bond. ### Conclusion The reagents used in the transformation of R-CH₂-CCl₂-R to R-C≡C-R are: 1. Alcoholic KOH (for the first elimination to form an alkene) 2. Sodium amide (NaNH₂) (for the second elimination to form an alkyne) **Final Answer:** The reagents used are alcoholic KOH and NaNH₂.

To solve the problem of transforming R-CH₂-CCl₂-R into R-C≡C-R, we need to identify the reagents used in this reaction. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the Starting Compound The starting compound is R-CH₂-CCl₂-R, which is a 1,1-dihaloalkane. This compound contains two chlorine atoms attached to a carbon atom that is also connected to two R groups. **Hint:** Look for the functional groups and the structure of the starting compound to understand what kind of reactions it can undergo. ### Step 2: First Reagent - Alcoholic KOH ...
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ALLEN-ALKENE, ALKANE & ALKYNE -EXCERSISE-3
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