Acetylene when treated with dilute `HCl` at `60^(@)C(333K)` in presence of `HgCl_(2)` produces-

Options

A. Methyl chloride
B. Vinyl chloride
C. Acetaldehyde
D. Formaidelhyde

Explanation

To solve the problem of what acetylene produces when treated with dilute HCl at 60°C (333 K) in the presence of HgCl2, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactant in this case is acetylene, which has the chemical formula \( \text{HC} \equiv \text{CH} \).

2. **Understand the Reaction Conditions**: The reaction occurs in the presence of dilute hydrochloric acid (HCl) and mercuric chloride (HgCl2) at a temperature of 60°C (333 K). This indicates that we are likely dealing with an electrophilic addition reaction.

3. **Write the Reaction**: When acetylene reacts with dilute HCl in the presence of HgCl2, the reaction proceeds via the formation of a vinyl cation. The reaction can be represented as follows:
\[ \text{HC} \equiv \text{CH} + \text{HCl} \xrightarrow{\text{HgCl}_2} \text{CH}_2=\text{CHCl} \]
Here, the acetylene adds HCl across the triple bond.

4. **Identify the Product**: The product formed is vinyl chloride, which has the chemical structure \( \text{CH}_2=\text{CHCl} \). This is a compound where a chlorine atom is added to the double bond of the ethylene structure.

5. **Select the Correct Option**: From the options given, we need to identify which one corresponds to the product vinyl chloride. The options are:
- A) Methyl chloride
- B) Vinyl chloride
- C) Acetaldehyde
- D) Formaldehyde

The correct answer is **B) Vinyl chloride**.

### Final Answer:
The product formed when acetylene is treated with dilute HCl at 60°C in the presence of HgCl2 is **vinyl chloride**.

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