Alkaline `KMnO_(4)`. Oxidizes acetylene to -

Options

A. Acetic acid
B. Glyoxal
C. Oxalic acid
D. Ethylene glycol

Explanation

To solve the question regarding the oxidation of acetylene by alkaline KMnO₄, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- Acetylene is the simplest alkyne, with the chemical formula C₂H₂ (or CH≡CH).
- Alkaline KMnO₄ is a strong oxidizing agent used for oxidation reactions.

2. **Understand the Reaction**:
- Alkaline KMnO₄ oxidizes alkynes and alkenes to form diols (compounds with two hydroxyl groups, -OH).
- The reaction involves the addition of hydroxyl groups across the double or triple bond.

3. **Write the Reaction**:
- The reaction of acetylene (C₂H₂) with alkaline KMnO₄ can be represented as:
\[ \text{C}_2\text{H}_2 + \text{KMnO}_4 \xrightarrow{\text{KOH}} \text{C}_2\text{H}_6\text{O}_2 \]
- Here, C₂H₆O₂ represents ethylene glycol (or ethane-1,2-diol).

4. **Identify the Product**:
- The product formed from the reaction is ethylene glycol (C₂H₆O₂), which is also known as ethane-1,2-diol.

5. **Reduction of KMnO₄**:
- During this reaction, KMnO₄ is reduced to manganese dioxide (MnO₂).

6. **Conclusion**:
- Therefore, the final answer to the question is that alkaline KMnO₄ oxidizes acetylene to form ethylene glycol (C₂H₆O₂).

### Final Answer:
Alkaline KMnO₄ oxidizes acetylene to ethylene glycol (C₂H₆O₂).

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