Excess of `CH_(3)COOH` is reacted with `CH-=CH` in presence of `Hg^(2+)`, the product is -

Options

A. `CH_(3)CH(OOC CH_(3))_(2)`
B. `CH_(2)=CH(OOC CH_(3))`
C. `(CH_(3)COO)CH_(2)-CH_(2)(OOC CH_(3))`
D. None of these

Explanation

To solve the problem, we need to analyze the reaction between acetylene (CH≡CH) and acetic acid (CH₃COOH) in the presence of mercuric ions (Hg²⁺). Let's break down the steps involved in this reaction.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- We have acetylene (HC≡CH) and acetic acid (CH₃COOH).
- The presence of Hg²⁺ indicates that this is a reaction involving an electrophilic addition mechanism.

2. **Reaction Conditions**:
- The reaction is carried out at a temperature of 353 Kelvin, which is suitable for facilitating the addition reaction.

3. **Electrophilic Addition**:
- The triple bond in acetylene (HC≡CH) is highly reactive and can undergo electrophilic addition.
- The Hg²⁺ ion acts as a catalyst, facilitating the addition of acetic acid to the triple bond.

4. **Formation of Vinyl Acetate**:
- The first step involves the addition of one molecule of acetic acid to the acetylene, resulting in the formation of vinyl acetate (H₂C=CHOCOCH₃).
- This compound has a double bond between the carbon atoms, with one of the carbons bonded to an acetoxy group.

5. **Further Reaction**:
- In the presence of excess acetic acid and Hg²⁺, the vinyl acetate can undergo further reaction.
- A second molecule of acetic acid adds to the vinyl acetate, resulting in the formation of a diacetate compound.

6. **Final Product**:
- The final product formed is ethylidene diacetate (CH₃COOCH₂C(=O)OCH₃), which contains two acetate groups attached to a carbon atom.

### Final Answer:
The product of the reaction between excess acetic acid and acetylene in the presence of Hg²⁺ is **ethylidene diacetate (CH₃COOCH₂C(=O)OCH₃)**.

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