Propene is allowed to react with `B_(2)D_(6)` and the product is treated with acetic acid. The final product obtained is -

Options

A. (a)`1-`deuteriopropane
B. (b)`2-`deuteriopropane
C. `(c)1-`deuteriopropene
D. (d)`2-`deuteriopropene

Answer

To solve the question, we need to analyze the reaction of propene with B2D6 and then with acetic acid. Here’s a step-by-step breakdown of the process:

### Step 1: Identify the Reactants
The reactant is propene, which has the molecular formula C3H6. It can be represented as:
\[ \text{CH}_3\text{CH}=\text{CH}_2 \]

### Step 2: Understand the Reaction with B2D6
B2D6 (Diborane) is used in hydroboration reactions. In this case, it will add across the double bond of propene. The reaction proceeds as follows:
- The boron atom from B2D6 will add to the less substituted carbon atom (the terminal carbon), while the deuterium (D) will add to the more substituted carbon atom.

### Step 3: Write the Reaction
When propene reacts with B2D6, the addition occurs as follows:
\[ \text{CH}_3\text{CH}=\text{CH}_2 + \text{B}_2\text{D}_6 \rightarrow \text{CH}_3\text{CH}(\text{D})\text{CH}_2\text{B} \]
This results in the formation of an organoborane intermediate:
\[ \text{CH}_3\text{CH}(\text{D})\text{CH}_2\text{B} \]

### Step 4: Treatment with Acetic Acid
Next, the organoborane intermediate is treated with acetic acid (CH3COOH). This step involves hydrolysis, where the boron atom is replaced by a hydrogen atom:
\[ \text{CH}_3\text{CH}(\text{D})\text{CH}_2\text{B} + \text{CH}_3\text{COOH} \rightarrow \text{CH}_3\text{CH}(\text{D})\text{CH}_3 + \text{B(OH)}_3 \]
The deuterium (D) remains on the more substituted carbon.

### Step 5: Final Product
The final product after the reaction with acetic acid is:
\[ \text{CH}_3\text{CH}(\text{D})\text{CH}_3 \]
This compound is known as 2-deuteropropane.

### Step 6: IUPAC Naming
The IUPAC name of the final product is 2-deuteropropane.

### Final Answer
The final product obtained is **2-deuteropropane**.

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