The addition of `HCl` to `1-`phenylpropene gives-

Options

A. `(a)C_(6)H_(5)CHClCH_(2)CH_(6)`
B. (b)`C_(6)H_(5)CH_(2)CHClCH_(2)`
C. (c)`C_(6)H_(5)CH_(2)CH_(2)CH_(2)Cl`
D. (d)`C_(6)H_(5)CH(CH_(3))CH_(2)Cl`

Answer

To solve the question regarding the addition of HCl to 1-phenylpropene, we will follow these steps:

### Step-by-Step Solution:

1. **Identify the Structure of 1-Phenylpropene**:
- 1-Phenylpropene consists of a propene chain (C3H6) with a phenyl group (C6H5) attached to the first carbon. The structure can be represented as:
\[ \text{C}_6\text{H}_5-\text{C}=\text{C}(\text{H})-\text{CH}_3 \]

2. **Understand the Reaction with HCl**:
- When HCl is added to alkenes, it dissociates into H⁺ and Cl⁻ ions. The H⁺ ion will add to one of the carbons in the double bond, while the Cl⁻ ion will add to the other carbon.

3. **Formation of Carbocations**:
- The addition of H⁺ to the double bond can lead to the formation of two possible carbocations:
- **Intermediate 1**: H⁺ adds to the terminal carbon (C2), leading to a carbocation on C1.
- **Intermediate 2**: H⁺ adds to the internal carbon (C1), leading to a carbocation on C2.
- The structures of the intermediates can be represented as:
- **Intermediate 1**:
\[ \text{C}_6\text{H}_5-\text{C}^+(\text{H})-\text{CH}_2-\text{CH}_3 \]
- **Intermediate 2**:
\[ \text{C}_6\text{H}_5-\text{C}(\text{H})-\text{C}^+(\text{Cl})-\text{H} \]

4. **Stability of Carbocations**:
- The stability of the carbocations is crucial. The carbocation that is resonance-stabilized by the phenyl group will be more stable. Therefore, the carbocation formed in Intermediate 1 is more stable due to resonance with the benzene ring.

5. **Formation of Products**:
- From Intermediate 1, the Cl⁻ will add to the more stable carbocation, leading to the final product:
\[ \text{C}_6\text{H}_5-\text{C}(\text{Cl})-\text{CH}_2-\text{CH}_3 \]
- This product can be named as 1-chloro-1-phenylpropane.

6. **Final Answer**:
- The product formed from the addition of HCl to 1-phenylpropene is:
\[ \text{C}_6\text{H}_5-\text{C}(\text{Cl})-\text{CH}_2-\text{CH}_3 \quad \text{(1-chloro-1-phenylpropane)} \]