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The ease of formation of free radicals f...

The ease of formation of free radicals follows the order -

A

(a)`3^(@)gt2^(@)gt1^(@)gtCH_(3)`

B

(b)`CH_(3)gt1^(@)gt2^(@)gt3^(@)`

C

(c)`1^(@)gt2^(@)gt3^(@)gtCH_(3)`

D

(d)`2^(@)gt1^(@)gt3^(@)gtCH_(3)`

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The correct Answer is:
To determine the order of ease of formation of free radicals, we can analyze the stability of free radicals, which follows a similar trend to that of carbocations. Here's a step-by-step solution: ### Step-by-Step Solution: 1. **Understanding Free Radicals**: Free radicals are species that contain an unpaired electron. Their stability is influenced by the surrounding groups attached to the carbon atom bearing the unpaired electron. 2. **Stability of Carbocations**: The stability of carbocations is well-known and follows the order: - Tertiary (3°) > Secondary (2°) > Primary (1°) > Methyl (CH3+). This order is due to the inductive effect of alkyl groups, which donate electron density to the positively charged carbon, stabilizing it. 3. **Relating Carbocations to Free Radicals**: The stability of free radicals follows the same trend as that of carbocations. This is because both species are affected by the same inductive and hyperconjugative effects from alkyl groups. 4. **Identifying Free Radical Stability**: - Tertiary free radicals (R3C•) are more stable than secondary (R2CH•), which are more stable than primary (RCH2•), and finally, methyl (CH3•) is the least stable. - The presence of more alkyl groups around the carbon with the unpaired electron stabilizes the free radical due to similar electron-donating effects. 5. **Conclusion**: Therefore, the order of ease of formation of free radicals is: - Tertiary > Secondary > Primary > Methyl. ### Final Answer: The ease of formation of free radicals follows the order: **Tertiary > Secondary > Primary > Methyl**.
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ALLEN-ALKENE, ALKANE & ALKYNE -EXERCISE-1
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