Hydrocarbon (A) `C_(6)H_(10)`, on treatment with `H_(2)//Ni, H_(2)`/ Lindlar's catalylst and Na/liquid `NH_(3)` forms three different reduction products (B), ( C) and (D) respectively. (A) does not form any salt with ammoniacal `AgNO_(3)` solution, but forms a salt (E) on heating with `NaNH_(2)` in an inert solvent. Compound (E) reacts with `CH_(3)I` to give (F). Compound (D) on oxidative ozonolysis gives n-butanoic acid along with other product.
Give structures of (A) to (F) with proper reasoning.

Answer

To solve the problem step-by-step, we will identify the structures of compounds (A) to (F) based on the information provided.

### Step 1: Identify Compound (A)
Given that compound (A) has the molecular formula \(C_6H_{10}\), it can be classified as an alkyne since it follows the formula \(C_nH_{2n-2}\).

To satisfy the condition that (A) does not form a salt with ammoniacal \(AgNO_3\), it must be a non-terminal alkyne. A suitable structure for (A) is:
\[ \text{(A): } CH_3CH_2CH_2C \equiv C CH_3 \]
This is 2-heptyne, a non-terminal alkyne.

### Step 2: Identify Compound (B)
When compound (A) is treated with \(H_2\) in the presence of nickel (\(Ni\)), it undergoes complete hydrogenation to form an alkane:
\[ \text{(B): } CH_3CH_2CH_2CH_2CH_2CH_3 \]
This is hexane.

### Step 3: Identify Compound (C)
When compound (A) is treated with \(H_2\) using Lindlar's catalyst, it undergoes partial hydrogenation to form a cis-alkene:
\[ \text{(C): } CH_3CH_2CH_2C=CH_2 \]
This is cis-2-hexene.

### Step 4: Identify Compound (D)
When compound (A) is treated with sodium in liquid ammonia, it undergoes Birch reduction, resulting in a trans-alkene:
\[ \text{(D): } CH_3CH_2CH_2C=CHCH_3 \]
This is trans-2-hexene.

### Step 5: Identify Compound (E)
Compound (A) does not form a salt with ammoniacal \(AgNO_3\) but forms a salt (E) when heated with \(NaNH_2\) in an inert solvent:
\[ \text{(E): } CH_3CH_2CH_2C \equiv CNa \]
This is the sodium salt of the alkyne.

### Step 6: Identify Compound (F)
When compound (E) reacts with \(CH_3I\) (methyl iodide), it forms:
\[ \text{(F): } CH_3CH_2CH_2C \equiv CH_3 \]
This is 1-heptyne.

### Step 7: Additional Information for Compound (D)
Compound (D) on oxidative ozonolysis gives n-butanoic acid and another product:
The ozonolysis of trans-2-hexene (D) results in:
\[ \text{Products: } CH_3CH_2CH_2COOH \text{ (n-butanoic acid) and } CH_3COOH \text{ (acetic acid)} \]

### Summary of Structures:
- **(A)**: \( CH_3CH_2CH_2C \equiv C CH_3 \) (2-heptyne)
- **(B)**: \( CH_3CH_2CH_2CH_2CH_2CH_3 \) (hexane)
- **(C)**: \( CH_3CH_2CH_2C=CH_2 \) (cis-2-hexene)
- **(D)**: \( CH_3CH_2CH_2C=CHCH_3 \) (trans-2-hexene)
- **(E)**: \( CH_3CH_2CH_2C \equiv CNa \) (sodium salt of 2-heptyne)
- **(F)**: \( CH_3CH_2CH_2C \equiv CH_3 \) (1-heptyne)