In the following sequence of reactions, the alkene affords the compound `B`:
`CH_(3)CH_(2)CH=CHCH_(3)overset(O_(3))rarrAunderset(Zn)overset(H_(2)O)rarrB`
The compound `B` is

Options

A. `CH_(3)CH_(2)CHO`
B. `CH_(3)COCH_(3)`
C. `CH_(3)CH_(2)COCH_(3)`
D. None of these

Answer

To solve the problem, we need to analyze the given sequence of reactions step by step.

### Step 1: Identify the starting alkene
The starting alkene is given as:
\[ \text{CH}_3\text{CH}_2\text{CH}=\text{CHCH}_3 \]
This is 2-pentene.

### Step 2: Ozonolysis reaction
The first reaction involves ozonolysis, which is the reaction of the alkene with ozone (O₃).
In this reaction, the alkene undergoes cleavage to form an ozonide intermediate. The ozonolysis of 2-pentene will yield:
\[ \text{CH}_3\text{CH}_2\text{C}(\text{O})\text{O}\text{CH}(\text{O})\text{CH}_3 \]
This ozonide can be represented as:
\[ \text{CH}_3\text{CH}_2\text{C}(\text{O})\text{C}(\text{O})\text{CH}_3 \]

### Step 3: Reduction of ozonide
Next, the ozonide is treated with zinc (Zn) and water (H₂O). This step reduces the ozonide to carbonyl compounds (aldehydes or ketones). The reaction can be summarized as:
\[ \text{Ozonide} \xrightarrow{\text{Zn/H}_2\text{O}} \text{Aldehydes/Ketones} \]

In this case, the ozonide will yield:
1. **Butanal**: \(\text{CH}_3\text{CH}_2\text{CHO}\)
2. **Acetaldehyde**: \(\text{CH}_3\text{CHO}\)

### Step 4: Identify the final compound B
The final products from the ozonolysis and reduction are:
- Butanal (CH₃CH₂CHO)
- Acetaldehyde (CH₃CHO)

Thus, compound B consists of both butanal and acetaldehyde. However, since the question asks for the compound B, we can consider the major product, which is butanal.

### Final Answer:
The compound B is **Butanal (CH₃CH₂CHO)**.

---