`CH_(3)-CH=CH_(2)overset(NOCl)rarr` Product, product is :

Options

A. `CH_(3)-underset(Cl)underset(|)CH-CH_(2)-NO`
B. `CH_(4)-underset(OH)underset(|)(CH)-CH_(2)-Cl`
C. `CH_(4)-CH_(2)-CH_(4)-Cl`
D. `NO-CH_(2)-CH_(2)-CH_(2)-Cl`

Answer

To solve the question regarding the reaction of propene (CH₃-CH=CH₂) with nitrosyl chloride (NOCl), we will follow these steps:

### Step 1: Identify the Reactants
The reactants in this case are propene (CH₃-CH=CH₂) and nitrosyl chloride (NOCl).

### Step 2: Understand the Mechanism
In the reaction, nitrosyl chloride (NOCl) dissociates into Cl⁻ and N⁺=O. The Cl⁻ ion acts as a nucleophile and will attack one of the carbons in the double bond of the alkene (propene).

### Step 3: Determine the Site of Attack
The double bond in propene is between the second and third carbon atoms (C2 and C3). The Cl⁻ ion will preferentially attack the less substituted carbon (C2) due to Markovnikov's rule, leading to the formation of a more stable carbocation.

### Step 4: Form the Product
After the Cl⁻ ion attacks C2, the double bond is broken, and the nitrogen from NOCl will attach to the other carbon (C3). Therefore, the product will have a chlorine atom on C2 and a nitroso group (NO) on C3.

### Step 5: Write the Final Structure
The final structure of the product will be:
- C1: CH₃
- C2: CH (with Cl attached)
- C3: CH₂ (with NO attached)

Thus, the product can be represented as:
CH₃-CH(Cl)-CH₂-NO

### Final Answer
The product formed from the reaction of CH₃-CH=CH₂ with NOCl is propylene nitroso chloride, which can be represented as CH₃-CH(Cl)-CH₂-NO.

---