When `1`-pentyne `(A)` is treated with `4N` alcoholic `KOH` at `175^(@)C`, it is converted slowely into an equilibrium mixture of `1.3% 1`-pentyne `(A), 95.2%2`-pentyne `(B)`,and `3.5%` of `1,2`-pentadiene `(C )`. The equilibrium is maintained at `175^(@)C`. Calculate `DeltaG^(Theta)` for the following equilibria.
`B hArr A, DeltaG_(1)^(Theta) = ?`
`B hArr C, DeltaG_(2)^(Theta) = ?`
From the calculated values of `DeltaG_(1)^(Theta)` and `DeltaG_(2)^(Theta)`, indicate the order of stability of `A, B`, and `C`.

When 1 pentyne (A) is treated with 4N alcoholic KOH at 175^(@)C , it is slowly converted into an equilibrium mixture of 1.3% of 1 pentyne (A), 95.2% 2 -pentyne (B) and 3.5% of 1,2 -pentandiene (C ) . The equilibrium was maintained at 175^(@)C . Calculate DeltaG^(Theta) for the following equilibria: B hArr A, DeltaG^(Theta)underset(1) = ? B hArr C, DeltaG^(Theta)underset(2) =? From the calculated value of DeltaG^(Theta)underset(1) and DeltaG^(Theta)underset(2) , indicate the order of stability of A,B and C . Write a reasonable reaction mechanism showing all intermediates leading to A,B and C .

When 1 pentyne (A) is treated with 4N alcoholic KOH at 175^(@)C , it is slowly converted into an equilibrium mixture of 1.3% of 1 pentyne (A), 95.2% 2 -pentyne (B) and 3.5% of 1,2 -pentandiene (C ) . The equilibrium was maintained at 175^(@)C . calculate DeltaG^(Theta) for the following equilibria: B hArr A, DeltaG^(Theta)underset(1) = ? B hArr C, DeltaG^(Theta)underset(2) =? From the calculated value of DeltaG^(Theta)underset(1) and DeltaG^(Theta)underset(2) , indicate the order of stability of A,B and C .

Determine the values of equilibrium constant (K_C) and DeltaG^o for the following reaction :

If theta=pi/(4n) then the value of tanthetatan(2theta)tan(3theta)....tan((2n-1)theta) is

At equilibrium, Kp = 1 then the value of DeltaG^(@) will be equal to.....

Consider the following equations for a cell reaction, A + B rarr C + D , E^(@) = x "volt", Delta G= Delta G_(1) 2A + 2B rarr 2C + 2D, E^(@) = y "volt", DeltaG = DeltaG_(2) Then,

Which is not correct relationship between DeltaG^(Theta) and equilibrium constant K_(P) .

Calculate DeltaG^(Theta) for the following reaction: CO(g) +((1)/(2))O_(2)(g) rarr CO_(2)(g), DeltaH^(Theta) =- 282.84 kJ Given, S_(CO_(2))^(Theta)=213.8 J K^(-1) mol^(-1), S_(CO(g))^(Theta)= 197.9 J K^(-1) mol^(-1), S_(O_(2))^(Theta)=205.0 J K^(-1)mol^(-1) ,

The value of DeltaG^(@) for a reaction in aqueous phase having K_(c)=1, would be :

For the equilibrium, PCI_(5)(g) hArr PCI_(3)(g) +CI_(2)(g) at 25^(@)C K_(c) =1.8 xx 10^(-7) Calculate DeltaG^(Theta) for the reaction (R = 8.314 J K^(-1) mol^(-1)) .