Home
Class 12
CHEMISTRY
Ethylbenzene +Cl(2)overset("Light")rarr(...

Ethylbenzene `+Cl_(2)overset("Light")rarr`(main) compound is :

A

`o-& p-` Chloroethylbenzene

B

`1-`Chloroethylbenzene

C

`2-`Chloroethylbenzene

D

`m-`Chloroethylbenzene

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of what the main compound formed when ethylbenzene reacts with chlorine in the presence of light, we will follow these steps: ### Step-by-Step Solution: 1. **Identify the Reactants**: The reactants are ethylbenzene (C6H5C2H5) and chlorine gas (Cl2). Ethylbenzene consists of a benzene ring with an ethyl group attached. 2. **Understand the Reaction Type**: The reaction involves a free radical substitution mechanism. This is typical for alkanes and aromatic compounds when they react with halogens in the presence of light. 3. **Initiation Step**: In the presence of light, Cl2 undergoes homolytic cleavage to form two chlorine radicals (Cl•): \[ Cl_2 \xrightarrow{light} 2Cl• \] 4. **Formation of Radicals**: The chlorine radical can abstract a hydrogen atom from the ethyl group of ethylbenzene, forming an ethyl radical (C2H5•) and hydrochloric acid (HCl): \[ C_6H_5C_2H_5 + Cl• \rightarrow C_6H_5C_2H_4• + HCl \] 5. **Radical Stability**: The ethyl radical (C2H5•) can further react with another chlorine radical to form the main product. However, it is important to note that the benzyl radical (C6H5CH2•) can also be formed if the chlorine radical abstracts a hydrogen from the benzyl position: \[ C_6H_5C_2H_4• + Cl• \rightarrow C_6H_5C_2H_4Cl \quad (1-chloroethylbenzene) \] \[ C_6H_5CH_2• + Cl• \rightarrow C_6H_5CH_2Cl \quad (benzyl chloride) \] 6. **Product Distribution**: The major product is determined by the stability of the radicals formed. The benzyl radical is more stable than the ethyl radical due to resonance stabilization. Therefore, the major product will be 1-chloroethylbenzene (C6H5C2H4Cl). 7. **Final Products**: The two products formed are: - Major product: 1-chloroethylbenzene (C6H5C2H4Cl) - Minor product: Benzyl chloride (C6H5CH2Cl) ### Conclusion: The main compound formed when ethylbenzene reacts with Cl2 in the presence of light is **1-chloroethylbenzene**. ---

To solve the problem of what the main compound formed when ethylbenzene reacts with chlorine in the presence of light, we will follow these steps: ### Step-by-Step Solution: 1. **Identify the Reactants**: The reactants are ethylbenzene (C6H5C2H5) and chlorine gas (Cl2). Ethylbenzene consists of a benzene ring with an ethyl group attached. 2. **Understand the Reaction Type**: The reaction involves a free radical substitution mechanism. This is typical for alkanes and aromatic compounds when they react with halogens in the presence of light. ...
Promotional Banner

Topper's Solved these Questions

  • ALKENE, ALKANE & ALKYNE

    ALLEN|Exercise EXERCISE-1|119 Videos
  • ALKENE, ALKANE & ALKYNE

    ALLEN|Exercise EXERCISE-2|103 Videos
  • AIIMS 2019

    ALLEN|Exercise CHEMISTRY|40 Videos
  • ALKYL AND ARYL HALIDE

    ALLEN|Exercise EXERCISE-05 (B)|35 Videos

Similar Questions

Explore conceptually related problems

A overset(OBr^(-))(rarr) "CHBr"_(3) the compound is :

A overset(OBr^(-))(rarr) "CHBr"_(3) the compound is :

In the equation CH_(3)COOH+Cl_(2)overset("RedP")underset(-HCl)rarrA , the compound A is :

SiCl_(4)overset(H_(2)O)rarr(A)overset("Heat")rarr (B) overset(Na_(2)CO_(3))underset("Heat")rarr(C ) , The compound (C ) is

Compound (A) underset(HIO_(4))overset(1 mol of)(rarr) The compound (A) is:

CH_3CH_2 COOH overset(Cl_2//Fe)rarr (X) overset(Alc.) underset(KOH)rarr (Y) Compound (Y) is :

Et-N^(o+)-=C^(ɵ) underset(or HgO or O_(3))overset(Cl_(2)+DMSO)(rarr) . The compound (A) is:

In the equation CH_(3)COOH+Cl_(2)+underset(-HCl)overset("red P")toA . The compound A is :

ALLEN-ALKENE, ALKANE & ALKYNE -EXCERSISE-3
  1. Ethylbenzene +Cl(2)overset("Light")rarr(main) compound is :

    Text Solution

    |

  2. True or False

    Text Solution

    |

  3. Heating of beta-hydroxy acid gives lactones.

    Text Solution

    |

  4. Hunsdiecker reaction involve free radical in intermediate steps.

    Text Solution

    |

  5. Benzoic acid is stronger than methanoic acid but weaker than ethanoic ...

    Text Solution

    |

  6. Acid halides are more reactive than acid amides towards the hydrolysis...

    Text Solution

    |

  7. What happens when sodium benzoate is heated with soda lime?

    Text Solution

    |

  8. pK(a) and K(a) of an acid are connected by the relation.......

    Text Solution

    |

  9. Fill in the blank by choosing the appropriate word/words from those gi...

    Text Solution

    |

  10. Hell-Volhard-Zelinsky reaction involves the replacement of an ...........

    Text Solution

    |

  11. Carboxylic acids may be prepared by the reaction of Grigrand reagents ...

    Text Solution

    |

  12. Statement-I: Unlike the gtC=O group of aldehydes and ketones, the C=O ...

    Text Solution

    |

  13. Statement-I: CH(3)COCH(2)COOC(2)H(5) will give iodoform test. Becau...

    Text Solution

    |

  14. Statement-1: Acetic acid does not undergo haloform test. and State...

    Text Solution

    |

  15. Statement-I: Benzoic acid on nitration will give m- nitro benzoic ac...

    Text Solution

    |

  16. Statement-I: Acyl halide are more reactive than acid substance amide t...

    Text Solution

    |

  17. Amides undergo hydrolysis to yield carboxylic acid plus amine on heati...

    Text Solution

    |

  18. Amides undergo hydrolysis to yield carboxylic acid plus amine on heati...

    Text Solution

    |

  19. Acid halides are more reactive than acid amides towards the hydrolysis...

    Text Solution

    |

  20. When is treated with two equivalent of methyl magnesium iodide a...

    Text Solution

    |

  21. Ester gives nucleophilic addition reaction followed by elimination rea...

    Text Solution

    |